- Masa Atómica.
- Composición Porcentual.
- Formula Empírica.
NH4Cl
- Masa Atómica:
- N = 1 * 14g = 14g
- H = 4 * 1g = 4g
- Cl = 1 * 35,45g = 35,45g
----------------
= 53,45g
- Composición Porcentual:
- N = 1 * 14g = 14g
- H = 4 * 1g = 4g
- Cl = 1 * 35,45g = 35,45g
----------------
= 53,45g
°1 mol ~~~~> NH4Cl ~~~~> 53,45g
°53,45g = 100%
°14g N ~~~~> 100% NH4Cl
--------------------------- = 26,192g N%
53,45g NH4Cl
°4g H ~~~~> 100% NH4Cl
--------------------------- = 7,483g H%
53,45g NH4Cl
°35,45g Cl ~~~~> 100% NH4Cl
--------------------------- = 66,323g Cl%
53,45g NH4Cl --------------------------
= 99,998%
- Formula Empírica:
° N = 29,192% ~~~~> 29,192 N
° H = 7,483% ~~~~> 7,483 H
° Cl = 66,323% ~~~~> 66,323 Cl
° 29,192g N ~~~~> 1 mol N
-------------------- = 2,0851 mol N
14g N
° 7,483g H ~~~~> 1 mol H
-------------------- = 7,483 mol H
1g H
° 66,323g Cl ~~~~> 1 mol Cl
------------------- = 1,8708 mol Cl
35,45g Cl
° N = 2,0851
----------------- = 1
1,8708
° H = 7,483
----------------- = 4
1,8708
° Cl = 1,8708
----------------- = 0
1,8708
° Forma ~~~~> NH4Cl